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🌳 Class XI · Biology · Chapter 12

NCERT Solutions for Class 11 Biology Chapter 12: Respiration in Plants

Complete NCERT solutions for Class 11 Biology Chapter 12 Respiration in Plants — all 12 exercise questions with detailed answers, six NCERT-referenced diagrams (glycolysis, fermentation, Krebs’ cycle, ETS, ATP synthase, amphibolic pathway), comparison tables, exam tips and full chapter-at-a-glance revision notes.

12 questions14 diagrams14 tablesFull revision notes

Chapter at a glance — complete revision notes

Introduction — energy for life

  • All living organisms need energy for absorption, transport, movement, reproduction and even breathing. All this energy comes from the oxidation of macromolecules we call ‘food’.
  • Green plants and cyanobacteria prepare their own food by photosynthesis, trapping light energy as chemical energy in the bonds of carbohydrates (glucose, sucrose, starch). Only cells containing chloroplasts (usually in superficial layers) photosynthesise; so food must be translocated to all non-green parts, which also need it for oxidation.
  • Animals are heterotrophic (herbivores directly, carnivores indirectly); saprophytes such as fungi depend on dead and decaying matter. Ultimately all food respired comes from photosynthesis.
  • Cellular respiration = breakdown of food materials within the cell to release energy and trap it for ATP synthesis. Photosynthesis occurs in chloroplasts (eukaryotes) while breakdown occurs in the cytoplasm and mitochondria.
  • Respiration = the breaking of C–C bonds of complex compounds by oxidation within cells, releasing considerable energy. Compounds oxidised are respiratory substrates: usually carbohydrates, but proteins, fats and organic acids can also be used in some plants.
  • Energy is released in a series of slow, step-wise, enzyme-controlled reactions and trapped as ATP; it cannot be used directly, so ATP is the energy currency of the cell. The carbon skeletons produced are precursors for biosynthesis of other molecules.

12.1 Do plants breathe?

  • Plants require O2 for respiration and give out CO2; they have no specialised organs for gaseous exchange but have stomata and lenticels.
  • Why plants can do without respiratory organs: (1) each plant part takes care of its own gas exchange — very little transport of gases between parts; (2) plants have low demands — roots, stems and leaves respire at rates far lower than animals; only during photosynthesis are large volumes exchanged, and each leaf is adapted for it (O2 is released within the cell); (3) the distance gases must diffuse is short — in stems living cells lie in thin layers inside and beneath the bark with lenticels, interior cells are dead mechanical support; loose packing of parenchyma gives an interconnected network of air spaces.
  • Complete combustion of glucose: C6H12O6 + 6O2 → 6CO2 + 6H2O + Energy; most energy is given out as heat. The plant cell therefore oxidises glucose in several small steps, some large enough for the energy to be coupled to ATP synthesis.
  • First cells lived in an atmosphere lacking oxygen; present organisms include facultative anaerobes and obligate anaerobes. All living organisms retain the machinery to partially oxidise glucose without O2: glycolysis.
Sites of respiration in a eukaryotic cellSites of respiration in a eukaryotic cellCYTOPLASMGlycolysis: glucose → 2 pyruvic acid(2 ATP net, 2 NADH + H⁺)pyruvate entersMATRIXpyruvate → acetyl CoA + CO₂Krebs’ cycle (NADH, FADH₂, ATP)Inner membrane: ETS (I–IV)and ATP synthase (V)Intermembrane space(H⁺ accumulate)Outer membraneMatrix: pyruvate dehydrogenaseand Krebs’ cycle enzymesGlycolysis: cytoplasm · oxidative decarboxylation + Krebs’ cycle: mitochondrial matrix · ETS + oxidative phosphorylation: inner mitochondrial membrane© iBioKaare
Fig. — Sites of respiration in a eukaryotic cell (summary diagram drawn from NCERT sections 12.2–12.4) (original iBioKaare schematic). Compare with NCERT textbook — Sections 12.2–12.4 (summary diagram), PDF page 3 (book page 155) ↗

12.2 Glycolysis

Steps of glycolysisSteps of glycolysisGlucose (6C)Glucose-6-phosphate (6C)Fructose-6-phosphate (6C)Fructose-1,6-bisphosphate (6C)Triose phosphate (PGAL) (3C)2 × 1,3-bisphosphoglyceric acid (3C)2 × 3-phosphoglyceric acid (3C)2 × 2-phosphoglycerate2 × phosphoenolpyruvate (PEP)2 × Pyruvic acid (3C)Dihydroxyacetone phosphate (3C)⇄ATP → ADPhexokinaseisomerisationATP → ADPsplits into PGAL + DHAPPGAL oxidised;inorganic phosphate addedNAD⁺ → NADH + H⁺(the NADH step)ADP → ATP− H₂OADP → ATPNet: 2 ATP used (steps 1 and 3)4 ATP formed (2 per triose)2 NADH + H⁺ formedNet gain = 2 ATP + 2 NADH© iBioKaare
Fig. — Steps of glycolysis (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.1, PDF page 4 (book page 156) ↗
  • Glycolysis (Greek glycos = sugar, lysis = splitting) was given by Gustav Embden, Otto Meyerhof and J. Parnas — the EMP pathway. In anaerobic organisms it is the only process in respiration. It occurs in the cytoplasm and is present in all living organisms.
  • Glucose undergoes partial oxidation to two molecules of pyruvic acid. In plants the glucose comes from sucrose (end product of photosynthesis) or from storage carbohydrates; sucrose is converted to glucose and fructose by invertase.
  • Glucose and fructose are phosphorylated to glucose-6-phosphate by hexokinase; this isomerises to fructose-6-phosphate; later steps are the same. A chain of ten reactions, each under a different enzyme, forms pyruvate.
  • ATP is utilised at two steps: glucose → glucose-6-phosphate and fructose-6-phosphate → fructose-1,6-bisphosphate. Fructose-1,6-bisphosphate splits into dihydroxyacetone phosphate and 3-phosphoglyceraldehyde (PGAL).
  • NADH + H+ is formed at one step: PGAL → 1,3-bisphosphoglycerate (BPGA), with removal of two H atoms to NAD+ and addition of inorganic phosphate. ATP is formed at BPGA → 3-phosphoglyceric acid (PGA) and at PEP → pyruvic acid.
  • In-text question: ATP made directly = 4 per glucose (2 at each of the two steps, since each step occurs twice per glucose); minus 2 used = net 2 ATP.
  • Fate of pyruvate depends on cellular need: lactic acid fermentation, alcoholic fermentation or aerobic respiration (Krebs’ cycle).
Count per glucoseGlycolysis
ATP used2
ATP formed (gross)4
Net ATP2
NADH + H+2
Final product2 pyruvic acid

12.3 Fermentation

Major pathways of anaerobic respirationMajor pathways of anaerobic respiration (fermentation)GlucoseGlycolysis2 ATP (net)2 Pyruvic acidNADH + H⁺ → NAD⁺ (re-oxidised in both pathways)Pyruvic acid decarboxylase(in yeast, some bacteria)2 Acetaldehyde + 2 CO₂Alcohol dehydrogenase2 Ethanol (C₂H₅OH)ALCOHOLIC FERMENTATION(yeast; stops when alcohol reaches about 13%)Lactate dehydrogenase(some bacteria; animal muscle)2 Lactic acidLACTIC ACID FERMENTATION(muscle during exercise when O₂ is inadequate)Less than 7% of the energy of glucoseis released; net gain = 2 ATP per glucose© iBioKaare
Fig. — Major pathways of anaerobic respiration (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.2, PDF page 5 (book page 157) ↗
  • In fermentation (e.g., by yeast) glucose is incompletely oxidised under anaerobic conditions: pyruvic acid → CO2 + ethanol, catalysed by pyruvic acid decarboxylase and alcohol dehydrogenase. Some bacteria produce lactic acid; in animal muscle during exercise, with inadequate O2, pyruvic acid is reduced to lactic acid by lactate dehydrogenase. The reducing agent is NADH + H+, which is re-oxidised to NAD+ in both processes.
  • In both, less than 7 per cent of the energy of glucose is released, not all trapped as ATP; the processes are hazardous (acid or alcohol produced). Net ATP = 2 (4 formed − 2 used in glycolysis).
  • Yeast poisons itself when the alcohol concentration reaches about 13 per cent, so naturally fermented beverages cannot exceed about this; stronger drinks are obtained by distillation of fermented liquid.
  • Fermentation occurs in many prokaryotes, unicellular eukaryotes and germinating seeds (summary).

12.4 Aerobic respiration

  • Pyruvate is transported into the mitochondria. Crucial events: (1) complete oxidation of pyruvate by stepwise removal of all H atoms, leaving three molecules of CO2 — in the matrix; (2) passing the electrons removed to molecular O2 with simultaneous ATP synthesis — on the inner membrane.
  • Oxidative decarboxylation: pyruvic acid + CoA + NAD+ (Mg2+, pyruvate dehydrogenase) → acetyl CoA + CO2 + NADH + H+; two NADH from two pyruvates. Acetyl CoA enters the tricarboxylic acid (TCA) cycle, Krebs’ cycle (Hans Krebs).

12.4.1 Tricarboxylic acid cycle

The citric acid cycleThe citric acid (Krebs’) cycleCitric acid (6C)α-ketoglutaric acid (5C)Succinic acid (4C)Malic acid (4C)Oxaloacetic acid (4C)CITRIC ACID CYCLE(mitochondrial matrix)Pyruvate (3C)NAD⁺ → NADH + H⁺CO₂ releasedAcetyl coenzyme A (2C)condenses with OAA + H₂O(citrate synthase); CoA releasedCO₂NADH + H⁺CO₂, NADH + H⁺(via succinyl-CoA)GDP → GTP (→ ATP)CoAFAD → FADH₂NAD⁺ → NADH + H⁺Per acetyl group: 3 NADH + H⁺, 1 FADH₂, 1 GTP (ATP), 2 CO₂; OAA must be replenished and NAD⁺ / FAD regenerated© iBioKaare
Fig. — The citric acid cycle (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.3, PDF page 7 (book page 159) ↗
  • Starts with condensation of acetyl group with oxaloacetic acid (OAA) and water to give citric acid (citrate synthase; CoA released). Citrate → isocitrate; then two successive decarboxylations → α-ketoglutaric acid → succinyl-CoA; the rest oxidises succinyl-CoA to OAA so the cycle continues.
  • Conversion of succinyl-CoA to succinic acid forms GTP (substrate-level phosphorylation); in a coupled reaction GTP → GDP with ATP synthesised from ADP.
  • Three points where NAD+ → NADH + H+ and one point where FAD+ → FADH2. The cycle needs continued replenishment of OAA and regeneration of NAD+ and FAD+.
  • Net from one glucose (till TCA): CO2 released and 8 NADH + H+, 2 FADH2 and just 2 ATP in the TCA cycle.

12.4.2 Electron transport system (ETS) and oxidative phosphorylation

Electron transport systemElectron transport system (ETS) in the inner mitochondrial membraneINTERMEMBRANE SPACEMATRIXComplex INADH dehydrogenaseComplex IIComplex IIIcytochrome bc₁Complex IVcytochrome c oxidaseUQubiquinone (UQ)Cyt ce⁻e⁻e⁻e⁻NADH + H⁺ → NAD⁺Succinate → fumarateFAD → FADH₂½O₂ + 2H⁺ → H₂O(O₂ = final acceptor)H⁺H⁺H⁺F₀F₁ATP synthase (V)H⁺ flow backADP + iP → ATPProtons pumped into the intermembrane space by complexes I, III and IV; their return through ATP synthase drives ATP synthesis.© iBioKaare
Fig. — Electron transport system (ETS) (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.4, PDF page 8 (book page 160) ↗
  • NADH + H+ and FADH2 are oxidised through the ETS in the inner mitochondrial membrane and electrons are passed to O2 forming H2O.
  • Complex I (NADH dehydrogenase) oxidises NADH from the matrix and passes electrons to ubiquinone; complex II (FADH2, from succinate oxidation) also feeds ubiquinone; reduced ubiquinone (ubiquinol) passes electrons via cytochrome bc1 complex (complex III) to cytochrome c (mobile carrier on the outer surface of the inner membrane); complex IV (cytochrome c oxidase with cytochromes a and a3 and two copper centres) gives electrons to O2.
  • Electron flow is coupled to ATP synthase (complex V). 1 NADH → 3 ATP; 1 FADH2 → 2 ATP. O2 is the final hydrogen acceptor; its role is limited to the terminal stage but is vital because it drives the whole process by removing hydrogen.
  • Since the energy of oxidation–reduction (not light as in photophosphorylation) makes the proton gradient, the process is oxidative phosphorylation.
Diagrammatic presentation of ATP synthesis in mitochondriaATP synthesis in mitochondria (ATP synthase, complex V)INTERMEMBRANE SPACEMATRIXF₀ (channel)F₁(head piece)H⁺H⁺H⁺ADP + iPATPFor each ATP produced, 4 H⁺ passthrough F₀ from the intermembranespace to the matrixF₀ = integral membraneprotein complex (proton channel)F₁ = peripheral head piece(site of ATP synthesis)© iBioKaare
Fig. — Diagrammatic presentation of ATP synthesis in mitochondria (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.5, PDF page 9 (book page 161) ↗
  • ATP synthase has F1 headpiece (peripheral membrane protein complex with the catalytic site for ATP synthesis from ADP and inorganic phosphate) and F0 (integral membrane complex forming the proton channel). Passage of protons through F0 is coupled to the catalytic site of F1. For each ATP, 4 H+ pass through F0 from the intermembrane space to the matrix, down the electrochemical gradient.

12.5 The respiratory balance sheet

  • The net ATP gain per glucose can be calculated only as a theoretical exercise, based on assumptions: (1) a sequential, orderly pathway functions — glycolysis, TCA cycle and ETS one after another; (2) the NADH of glycolysis is transferred into mitochondria and undergoes oxidative phosphorylation; (3) none of the intermediates is used to synthesise other compounds; (4) only glucose is respired — no other substrate enters.
  • These are not valid in a living system (all pathways work simultaneously, substrates enter and leave, ATP is used as needed, enzyme rates are controlled), but the exercise shows the efficiency of the system. Net gain = 38 ATP per glucose in aerobic respiration.
StageReduced coenzymes / ATPATP equivalents
Glycolysis2 ATP (net) + 2 NADH + H+2 + 6 = 8
Pyruvate → acetyl CoA (2 pyruvates)2 NADH + H+6
Krebs’ cycle (2 turns)2 ATP (via GTP) + 6 NADH + H+ + 2 FADH22 + 18 + 4 = 24
Total38 ATP
  • Fermentation vs aerobic respiration: fermentation is only partial breakdown of glucose whereas aerobic respiration degrades it completely to CO2 and H2O; fermentation gives a net gain of only 2 ATP per glucose, aerobic respiration many more; NADH is oxidised to NAD+ slowly in fermentation but very vigorously in aerobic respiration.

12.6 Amphibolic pathway

Interrelationship among metabolic pathwaysInterrelationship among metabolic pathways: respiration of different organic moleculesPolysaccharides (starch, sucrose)GlucoseGlucose-6-phosphate → fructose-1,6-bisphosphateTriose phosphate (PGAL)GLYCOLYSISPyruvic acid(mitochondria)Acetyl CoAKREBS’ CYCLE(citric acid cycle)ETS → CO₂ + H₂O + energy (ATP)FatsGlycerolFatty acidsGlycerol enters as PGALFatty acids are degraded toacetyl CoA before enteringProteinsproteasesAmino acidsAmino acids (after deamination) enter atpyruvate, acetyl CoA or a Krebs’ cycle stepDouble-headed arrows: the same intermediates are withdrawn for synthesis (anabolism) — so the respiratory pathway is amphibolic.© iBioKaare
Fig. — Interrelationship among metabolic pathways showing respiration-mediated breakdown of different organic molecules to CO2 and H2O (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.6, PDF page 11 (book page 163) ↗
  • Glucose is the favoured substrate; all carbohydrates are usually first converted into glucose. Other substrates enter at later points: fats are broken into glycerol and fatty acids; fatty acids are degraded to acetyl CoA; glycerol enters as PGAL; proteins are degraded by proteases and the amino acids (after deamination) enter at some stage within the Krebs’ cycle or as pyruvate or acetyl CoA.
  • Respiration was traditionally considered catabolic. But the same compounds that enter are withdrawn from the pathway for synthesis: acetyl CoA is withdrawn for fatty acid synthesis, and intermediates link protein breakdown and synthesis. Since the pathway is involved in both catabolism (breakdown) and anabolism (synthesis), it is better considered an amphibolic pathway.

12.7 Respiratory quotient

  • RQ (respiratory ratio) = volume of CO2 evolved / volume of O2 consumed; it depends on the respiratory substrate.
  • Carbohydrates completely oxidised: C6H12O6 + 6O2 → 6CO2 + 6H2O + Energy; RQ = 6/6 = 1.0.
  • Fats: for tripalmitin, 2(C51H98O6) + 145O2 → 102CO2 + 98H2O + energy; RQ = 102/145 = 0.7 (less than 1).
  • Proteins: RQ about 0.9. In living organisms respiratory substrates are often more than one; pure proteins or fats are never used alone.
SubstrateRQ
Carbohydrates1.0
ProteinsAbout 0.9
Fats (e.g., tripalmitin)0.7 (less than 1)
Q1

Differentiate between (a) Respiration and Combustion (b) Glycolysis and Krebs’ cycle (c) Aerobic respiration and Fermentation

Answer

Concept — why the three pairs look alike but are not. Respiration is the controlled, enzyme-driven oxidation of food inside living cells, in which the energy of C–C bonds is released in small instalments and trapped as ATP. All three pairs below compare steps of this one story (or its non-living look-alike, combustion), so the differences lie in where the reaction occurs, whether oxygen is needed, how much energy is trapped and what the end products are.

(a) Respiration and combustion

FeatureRespirationCombustion
Site / natureTakes place inside living cells (cytoplasm and mitochondria); a biological processTakes place outside living systems, e.g., burning of wood or glucose in a flame; a purely chemical process
EnzymesControlled by a series of enzymes at each stepNo enzymes are involved
Number of stepsGlucose is oxidised in many small, step-wise reactionsOxidation occurs in a single, rapid, uncontrolled step
Fate of energyPart of the energy is trapped as chemical energy in ATP (the energy currency); the rest escapes as heatNearly all the energy is given out as heat (and light); none is stored as ATP
TemperatureOccurs at the low temperature of the organismNeeds a high ignition temperature
Usefulness of energyEnergy is released gradually, so the cell can use it for synthesis and other workEnergy is released at once and cannot be used by a cell

The complete combustion of glucose, C6H12O6 + 6O2 → 6CO2 + 6H2O + Energy, has the same overall equation as aerobic respiration; the real difference is that a cell oxidises glucose not in one step but in several small steps, some of which are just large enough for the energy to be coupled to ATP synthesis.

(b) Glycolysis and Krebs’ cycle (TCA cycle)

FeatureGlycolysis (EMP pathway)Krebs’ cycle (TCA / citric acid cycle)
MeaningGreek glycos = sugar, lysis = splitting; breakdown of glucose to pyruvic acidTricarboxylic acid cycle, named after Hans Krebs; oxidation of acetyl CoA to CO2
Proposed byGustav Embden, Otto Meyerhof and J. ParnasHans Krebs
SiteCytoplasm (cytosol) of the cellMatrix of the mitochondria (in eukaryotes)
OccurrencePresent in all living organismsOnly in aerobic organisms (mitochondria needed)
OxygenDoes not need O2 (partial oxidation)Needs O2, because NADH and FADH2 must be re-oxidised through the ETS
Starts with / ends withStarts with glucose (6C); ends with 2 molecules of pyruvic acid (3C)Starts with acetyl CoA (2C) condensing with oxaloacetic acid (4C) to give citric acid (6C); ends by regenerating OAA
NatureLinear chain of ten reactionsCyclic pathway
Direct yieldNet 2 ATP (4 formed − 2 used) and 2 NADH + H+ per glucosePer acetyl CoA: 3 NADH + H+, 1 FADH2, 1 GTP/ATP and 2 CO2
CO2None releasedCO2 released (decarboxylation)

(c) Aerobic respiration and fermentation

FeatureAerobic respirationFermentation
OxygenOccurs in the presence of O2Occurs under anaerobic conditions
Breakdown of glucoseComplete — to CO2 and H2OPartial (incomplete) — to ethanol + CO2 or lactic acid
ATP gainMany more ATP (theoretically 38 per glucose)Net gain of only 2 ATP per glucose (from glycolysis)
Energy releasedAll the energy of the substrate is availableLess than 7 per cent of the energy in glucose is released
NADH oxidationNADH is oxidised to NAD+ very vigorously through the ETSNADH is oxidised to NAD+ rather slowly
SiteCytoplasm + mitochondriaCytoplasm only
End productsHarmless CO2 and H2OHazardous acid or alcohol

Extra depth. Glycolysis is the common first stage of both aerobic respiration and fermentation: only after pyruvic acid is formed does the pathway split depending on O2 supply and on the organism. This is why glycolysis is considered the most ancient pathway — the first cells lived in an oxygen-free atmosphere and all organisms still keep the enzymes to oxidise glucose partially without O2.

Exam tip: For any “differentiate” question write a table with at least 5 rows; NCERT-based pairs examiners expect are site, O2 need, ATP yield and products.
Exam tip: Remember the one-line contrast for (a): respiration = enzyme-controlled, step-wise, energy trapped as ATP; combustion = uncontrolled, single step, energy lost as heat.

Conclusion: Respiration differs from combustion in being enzyme-controlled, step-wise and ATP-generating; glycolysis (cytoplasm, anaerobic, glucose → 2 pyruvate) differs from the Krebs’ cycle (matrix, oxygen-dependent, acetyl CoA → CO2); and aerobic respiration oxidises glucose completely with a high ATP yield whereas fermentation is partial with a net gain of only 2 ATP.

Q2

What are respiratory substrates? Name the most common respiratory substrate.

Answer

Concept. The breaking of C–C bonds of complex compounds through oxidation within the cells, leading to the release of a considerable amount of energy, is called respiration. The compounds that are oxidised during this process are known as respiratory substrates.

  • Carbohydrates are the usual substrates. Usually carbohydrates are oxidised to release energy. All carbohydrates are first converted into glucose before they are respired — in plants this glucose is derived from sucrose, the end product of photosynthesis, or from storage carbohydrates such as starch. Sucrose is split by the enzyme invertase into glucose and fructose.
  • Other substrates under certain conditions. Proteins, fats and even organic acids can be used as respiratory substances in some plants, under certain conditions. They do not enter the pathway at the first step: fats are broken to glycerol and fatty acids (fatty acids → acetyl CoA; glycerol → PGAL), and proteins are degraded by proteases to amino acids which, after deamination, enter at pyruvate, acetyl CoA or a step of the Krebs’ cycle.
  • Most common substrate: glucose. Glucose is the favoured (most common) respiratory substrate. In living organisms the substrates are often more than one — pure proteins or fats are never used alone.
SubstrateEnters respiratory pathway asRespiratory quotient
Carbohydrate (glucose)Glucose → glycolysis1.0
Fat (e.g., tripalmitin)Glycerol → PGAL; fatty acids → acetyl CoA0.7
ProteinAmino acids → pyruvate / acetyl CoA / Krebs’ cycle intermediatesAbout 0.9

Extra depth. Energy in a respiratory substrate is not released free in the cell or in one step; it is released in slow, enzyme-controlled steps and trapped in ATP. Because ATP, not the substrate itself, is what the cell uses, ATP is called the energy currency of the cell, while the carbon skeletons produced are used as precursors for biosynthesis of other molecules.

Exam tip: Write “glucose” as the answer to “most common substrate” and add that other substrates enter at later steps — this earns the extra mark.
Exam tip: Link the answer to RQ: the substrate decides whether RQ is 1 (carbohydrate), about 0.9 (protein) or less than 1 (fat).

Conclusion: Respiratory substrates are the organic compounds oxidised in respiration to release energy; carbohydrates, and above all glucose, are the most common substrate, while fats, proteins and organic acids serve under certain conditions.

Q3

Give the schematic representation of glycolysis?

Answer

Concept. The term glycolysis originated from the Greek words glycos (sugar) and lysis (splitting). The scheme was given by Gustav Embden, Otto Meyerhof and J. Parnas, so it is often called the EMP pathway. It occurs in the cytoplasm of all living organisms; glucose undergoes partial oxidation to form two molecules of pyruvic acid through a chain of ten reactions, each controlled by a different enzyme.

Steps of glycolysisSteps of glycolysisGlucose (6C)Glucose-6-phosphate (6C)Fructose-6-phosphate (6C)Fructose-1,6-bisphosphate (6C)Triose phosphate (PGAL) (3C)2 × 1,3-bisphosphoglyceric acid (3C)2 × 3-phosphoglyceric acid (3C)2 × 2-phosphoglycerate2 × phosphoenolpyruvate (PEP)2 × Pyruvic acid (3C)Dihydroxyacetone phosphate (3C)⇄ATP → ADPhexokinaseisomerisationATP → ADPsplits into PGAL + DHAPPGAL oxidised;inorganic phosphate addedNAD⁺ → NADH + H⁺(the NADH step)ADP → ATP− H₂OADP → ATPNet: 2 ATP used (steps 1 and 3)4 ATP formed (2 per triose)2 NADH + H⁺ formedNet gain = 2 ATP + 2 NADH© iBioKaare
Fig. — Steps of glycolysis (EMP pathway) (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.1, PDF page 4 (book page 156) ↗
  1. Entry of sugar. Sucrose is converted into glucose and fructose by invertase. Glucose (and fructose) is phosphorylated to glucose-6-phosphate by hexokinase, using 1 ATP (first ATP utilised).
  2. Isomerisation. Glucose-6-phosphate isomerises to fructose-6-phosphate.
  3. Second phosphorylation. Fructose-6-phosphate → fructose-1,6-bisphosphate using a second ATP (second ATP utilised).
  4. Splitting. Fructose-1,6-bisphosphate splits into dihydroxyacetone phosphate and 3-phosphoglyceraldehyde (PGAL); from here on every step occurs twice per glucose molecule.
  5. Oxidation (NADH formed). PGAL is oxidised, with inorganic phosphate, to 1,3-bisphosphoglycerate (BPGA); two hydrogen atoms (two redox equivalents) are transferred to NAD+ forming NADH + H+ — the only NADH-forming step.
  6. First ATP gain. BPGA → 3-phosphoglyceric acid (PGA); the energy is trapped by forming ATP (substrate-level phosphorylation).
  7. Rearrangement and dehydration. PGA → 2-phosphoglycerate → phosphoenolpyruvate (PEP) with loss of H2O.
  8. Second ATP gain. PEP → pyruvic acid, with synthesis of another ATP.
Glucose (6C)→Glucose-6-P→Fructose-6-P→Fructose-1,6-bisP→PGAL + DHAP (3C each)→BPGA→PGA→PEP→Pyruvic acid (3C) × 2
ItemPer glucose molecule
ATP utilised2 (steps 1 and 3)
ATP produced directly4 (2 at BPGA → PGA, 2 at PEP → pyruvate)
Net ATP gain2
NADH + H+2
Final product2 pyruvic acid

Extra depth. NCERT asks: how many ATP molecules are directly synthesised from one glucose? Four are made and two are spent, so the net direct gain is two ATP. Pyruvic acid is the key product, and its fate depends on the cell: lactic acid fermentation, alcoholic fermentation or aerobic respiration through the Krebs’ cycle.

Exam tip: Learn the three ATP/NADH landmarks: ATP used at glucose → G-6-P and F-6-P → F-1,6-bisP; NADH formed at PGAL → BPGA; ATP formed at BPGA → PGA and PEP → pyruvate.
Exam tip: In the diagram label enzymes only if asked; always mark carbon numbers (6C, 3C) and the six-carbon to two three-carbon split.

Conclusion: Glycolysis is a ten-step cytoplasmic pathway converting one glucose into two pyruvic acid with a net gain of 2 ATP and 2 NADH + H+.

Q4

What are the main steps in aerobic respiration? Where does it take place?

Answer

Concept. Aerobic respiration is the process that leads to a complete oxidation of organic substances in the presence of oxygen, releasing CO2, water and a large amount of energy present in the substrate. It is the most common type of respiration in higher organisms and, in eukaryotes, takes place within the mitochondria (after glycolysis in the cytoplasm).

The two crucial events (NCERT): (i) the complete oxidation of pyruvate by the stepwise removal of all hydrogen atoms, leaving three molecules of CO2; and (ii) the passing on of the electrons removed as part of the hydrogen atoms to molecular O2 with simultaneous synthesis of ATP.

StepProcessSite
1Glycolysis — glucose → 2 pyruvic acid (net 2 ATP, 2 NADH)Cytoplasm
2Transport of pyruvate from the cytoplasm into mitochondriaMitochondrial membranes
3Oxidative decarboxylation of pyruvate by pyruvic dehydrogenase (needs NAD+, coenzyme A, Mg2+) → acetyl CoA + CO2 + NADH + H+Mitochondrial matrix
4Tricarboxylic acid (Krebs’) cycle — acetyl CoA + OAA → citric acid → … → OAA; CO2, NADH, FADH2 and GTP/ATP formedMitochondrial matrix
5Electron transport system (ETS) and oxidative phosphorylation — NADH and FADH2 oxidised; electrons passed to O2, forming H2O; ATP made by ATP synthaseInner mitochondrial membrane
Glucose→Glycolysis (cytoplasm)→Pyruvic acid→Acetyl CoA (matrix)→Krebs’ cycle (matrix)→ETS + oxidative phosphorylation (inner membrane)→CO2 + H2O + ATP
Sites of respiration in a eukaryotic cellSites of respiration in a eukaryotic cellCYTOPLASMGlycolysis: glucose → 2 pyruvic acid(2 ATP net, 2 NADH + H⁺)pyruvate entersMATRIXpyruvate → acetyl CoA + CO₂Krebs’ cycle (NADH, FADH₂, ATP)Inner membrane: ETS (I–IV)and ATP synthase (V)Intermembrane space(H⁺ accumulate)Outer membraneMatrix: pyruvate dehydrogenaseand Krebs’ cycle enzymesGlycolysis: cytoplasm · oxidative decarboxylation + Krebs’ cycle: mitochondrial matrix · ETS + oxidative phosphorylation: inner mitochondrial membrane© iBioKaare
Fig. — Sites of respiration in a eukaryotic cell — glycolysis in cytoplasm; link reaction and Krebs’ cycle in matrix; ETS on inner membrane (original iBioKaare schematic). Compare with NCERT textbook — Sections 12.2–12.4, PDF page 3 (book page 155) ↗

Extra depth. Note that the first process (removal of hydrogen/CO2) occurs in the matrix, whereas the second (ETS) is located on the inner membrane. During the link reaction two NADH are produced from two molecules of pyruvic acid (one glucose). O2 acts only at the terminal stage but is vital because it removes hydrogen from the system and so drives the whole process.

Exam tip: Present the answer as a numbered list of 4–5 steps with the exact site against each — marks are usually split between “steps” and “place”.
Exam tip: Do not say the Krebs’ cycle itself needs O2 directly — O2 is used at the ETS; the cycle depends on it only for re-oxidation of NADH and FADH2.

Conclusion: Aerobic respiration comprises glycolysis, oxidative decarboxylation of pyruvate, the Krebs’ cycle and ETS with oxidative phosphorylation; the last three occur in the mitochondria (matrix and inner membrane).

Q5

Give the schematic representation of an overall view of Krebs’ cycle.

Answer

Concept. The acetyl CoA formed from pyruvate enters a cyclic pathway, the tricarboxylic acid (TCA) cycle, more commonly called Krebs’ cycle after Hans Krebs, who first elucidated it. It runs in the matrix of the mitochondria and oxidises the acetyl group completely to CO2, while capturing the hydrogen as NADH + H+ and FADH2.

The citric acid cycleThe citric acid (Krebs’) cycleCitric acid (6C)α-ketoglutaric acid (5C)Succinic acid (4C)Malic acid (4C)Oxaloacetic acid (4C)CITRIC ACID CYCLE(mitochondrial matrix)Pyruvate (3C)NAD⁺ → NADH + H⁺CO₂ releasedAcetyl coenzyme A (2C)condenses with OAA + H₂O(citrate synthase); CoA releasedCO₂NADH + H⁺CO₂, NADH + H⁺(via succinyl-CoA)GDP → GTP (→ ATP)CoAFAD → FADH₂NAD⁺ → NADH + H⁺Per acetyl group: 3 NADH + H⁺, 1 FADH₂, 1 GTP (ATP), 2 CO₂; OAA must be replenished and NAD⁺ / FAD regenerated© iBioKaare
Fig. — The citric acid (Krebs’) cycle — overall view (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.3, PDF page 7 (book page 159) ↗
  1. Link reaction (before the cycle). Pyruvic acid (3C) + CoA + NAD+ → acetyl CoA (2C) + CO2 + NADH + H+, catalysed by pyruvic dehydrogenase (with Mg2+).
  2. Condensation. Acetyl CoA (2C) combines with oxaloacetic acid (OAA, 4C) and water to form citric acid (6C); the enzyme is citrate synthase and CoA is released.
  3. Isomerisation. Citrate is isomerised to isocitrate.
  4. First decarboxylation. Isocitrate → α-ketoglutaric acid (5C) + CO2; NAD+ → NADH + H+.
  5. Second decarboxylation. α-Ketoglutaric acid → succinyl-CoA (4C) + CO2; another NADH + H+.
  6. Substrate-level phosphorylation. Succinyl-CoA → succinic acid; a molecule of GTP is synthesised, which is converted to GDP with simultaneous synthesis of ATP from ADP.
  7. Regeneration of OAA. Succinic acid → (FAD+ → FADH2) → malic acid → (NAD+ → NADH + H+) → oxaloacetic acid, ready to accept another acetyl group.
Pyruvate (3C)→Acetyl CoA (2C)→Citric acid (6C)→α-Ketoglutaric acid (5C)→Succinic acid (4C)→Malic acid (4C)→Oxaloacetic acid (4C)→back to citric acid
OutputPer acetyl CoA (one turn)Per glucose (two turns)
CO224 (plus 2 in the link reaction = 6 in all)
NADH + H+36
FADH212
GTP → ATP12

Extra depth. NCERT notes that there are three points where NAD+ is reduced to NADH + H+ and one point where FAD+ is reduced to FADH2. Continued oxidation of acetyl CoA requires continued replenishment of oxaloacetic acid and regeneration of NAD+ and FAD+ from NADH and FADH2 — which is done by the electron transport system. Counting the link reaction, one glucose gives CO2 together with eight NADH + H+ and two FADH2 besides two ATP.

Exam tip: Draw the cycle as a circle with carbon numbers 6C → 5C → 4C and mark the two CO2, three NADH, one FADH2, one GTP per turn.
Exam tip: Remember the summary sequence: citric acid → isocitrate → α-ketoglutarate → succinyl CoA → succinate → malate → OAA.

Conclusion: The Krebs’ cycle completely oxidises acetyl CoA to CO2 in the mitochondrial matrix, yielding NADH + H+, FADH2 and GTP/ATP, and regenerates oxaloacetic acid so the cycle continues.

Q6

Explain ETS.

Answer

Concept. The electron transport system (ETS) is the metabolic pathway through which electrons pass from one carrier to another. It is present in the inner mitochondrial membrane and releases and utilises the energy stored in NADH + H+ and FADH2 by passing their electrons finally to oxygen, which forms water.

Electron transport systemElectron transport system (ETS) in the inner mitochondrial membraneINTERMEMBRANE SPACEMATRIXComplex INADH dehydrogenaseComplex IIComplex IIIcytochrome bc₁Complex IVcytochrome c oxidaseUQubiquinone (UQ)Cyt ce⁻e⁻e⁻e⁻NADH + H⁺ → NAD⁺Succinate → fumarateFAD → FADH₂½O₂ + 2H⁺ → H₂O(O₂ = final acceptor)H⁺H⁺H⁺F₀F₁ATP synthase (V)H⁺ flow backADP + iP → ATPProtons pumped into the intermembrane space by complexes I, III and IV; their return through ATP synthase drives ATP synthesis.© iBioKaare
Fig. — Electron transport system (ETS) in the inner mitochondrial membrane (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.4, PDF page 8 (book page 160) ↗
  1. Complex I — NADH dehydrogenase. Electrons from NADH produced in the matrix during the citric acid cycle are oxidised by NADH dehydrogenase and transferred to ubiquinone located within the inner membrane.
  2. Complex II — succinate dehydrogenase (FADH2). Ubiquinone also receives reducing equivalents via FADH2 generated during oxidation of succinate in the cycle.
  3. Complex III — cytochrome bc1. The reduced ubiquinone (ubiquinol) is oxidised, passing electrons to cytochrome c.
  4. Cytochrome c. A small protein attached to the outer surface of the inner membrane that acts as a mobile carrier between complexes III and IV.
  5. Complex IV — cytochrome c oxidase. It contains cytochromes a and a3 and two copper centres; it passes electrons to O2, which is reduced (with H+) to H2O.
  6. Complex V — ATP synthase. As electrons pass through complexes I to IV the energy released is coupled to ATP synthase for synthesis of ATP from ADP and inorganic phosphate.
NADH + H+ (complex I)→Ubiquinone→Complex III→Cytochrome c→Complex IV→O2 → H2O

ATP yield. Oxidation of one molecule of NADH gives rise to 3 ATP, while that of one FADH2 produces 2 ATP (NCERT values). Oxygen acts as the final hydrogen (electron) acceptor; though its role is limited to the terminal stage, it is vital because it drives the whole process by removing hydrogen from the system.

Extra depth — why “oxidative phosphorylation”. In photophosphorylation the light energy builds the proton gradient, but in respiration the energy of oxidation–reduction is used for the same purpose; hence the process is called oxidative phosphorylation. (See Q11.)

Exam tip: List the carriers in order — I, ubiquinone, III, cytochrome c, IV, V — and mention that complex II (FADH2) feeds in at ubiquinone, not at complex I.
Exam tip: State clearly: NADH = 3 ATP, FADH2 = 2 ATP, and O2 is the final electron acceptor forming water.

Conclusion: The ETS is a chain of membrane-bound carriers (complexes I–IV, ubiquinone, cytochrome c) that moves electrons from NADH/FADH2 to O2 and powers ATP synthase (complex V) in the inner mitochondrial membrane.

Q7

Distinguish between the following: (a) Aerobic respiration and Anaerobic respiration (b) Glycolysis and Fermentation (c) Glycolysis and Citric acid Cycle

Answer

Concept. Anaerobic respiration and fermentation both start with glycolysis but differ from aerobic respiration in what happens to pyruvic acid. Pyruvic acid is handled in three ways by different cells: lactic acid fermentation, alcoholic fermentation or aerobic respiration.

(a) Aerobic respiration and anaerobic respiration

FeatureAerobic respirationAnaerobic respiration
O2Requires oxygenOccurs without oxygen
Glucose breakdownComplete oxidation to CO2 + H2OIncomplete: ethanol + CO2 (yeast) or lactic acid
SiteCytoplasm and mitochondriaCytoplasm
EnergyLarge amount (theoretically 38 ATP)Small: net 2 ATP; less than 7% of the glucose energy released
End productsHarmless CO2 and waterHazardous alcohol or acid
OccurrenceMost higher organismsMany prokaryotes, yeast, germinating seeds, and muscle cells under O2 shortage

(b) Glycolysis and fermentation

FeatureGlycolysisFermentation
MeaningBreakdown of glucose to 2 pyruvic acidConversion of pyruvic acid to ethanol + CO2 or lactic acid (by yeast / some bacteria / muscle)
EnzymesTen enzymes (hexokinase … pyruvate kinase)Pyruvic acid decarboxylase + alcohol dehydrogenase (alcoholic); lactate dehydrogenase (lactic)
NADHProduces NADH + H+Uses NADH + H+ as reducing agent; regenerates NAD+
ATPNet gain 2 ATPNo further ATP — the net gain stays 2 ATP per glucose
UniversalityOccurs in all living organisms, aerobic and anaerobicOnly under anaerobic conditions
Major pathways of anaerobic respirationMajor pathways of anaerobic respiration (fermentation)GlucoseGlycolysis2 ATP (net)2 Pyruvic acidNADH + H⁺ → NAD⁺ (re-oxidised in both pathways)Pyruvic acid decarboxylase(in yeast, some bacteria)2 Acetaldehyde + 2 CO₂Alcohol dehydrogenase2 Ethanol (C₂H₅OH)ALCOHOLIC FERMENTATION(yeast; stops when alcohol reaches about 13%)Lactate dehydrogenase(some bacteria; animal muscle)2 Lactic acidLACTIC ACID FERMENTATION(muscle during exercise when O₂ is inadequate)Less than 7% of the energy of glucoseis released; net gain = 2 ATP per glucose© iBioKaare
Fig. — Major pathways of anaerobic respiration — pyruvic acid to ethanol + CO2 or lactic acid (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.2, PDF page 5 (book page 157) ↗

(c) Glycolysis and citric acid cycle

FeatureGlycolysisCitric acid (Krebs’) cycle
SiteCytoplasmMitochondrial matrix
SubstrateGlucoseAcetyl CoA (from pyruvate)
Product2 pyruvic acid, 2 NADH, net 2 ATPCO2, NADH, FADH2, GTP/ATP; OAA regenerated
OxygenNot neededNeeded indirectly (to re-oxidise NADH, FADH2)
Pathway typeLinear, 10 stepsCyclic
OccurrenceAll organismsAerobic organisms only

Extra depth. In both lactic and alcoholic fermentation, NADH + H+ is reoxidised to NAD+; this keeps glycolysis running even without oxygen. Yeast poisons itself when alcohol reaches about 13 per cent, which limits natural fermentation; stronger drinks are obtained by distillation.

Exam tip: Tables of at least five points for each part are expected; the NCERT contrast (b) is that glycolysis is common to all, fermentation is a pyruvate fate in absence of O2.
Exam tip: Quote “less than seven per cent of glucose energy” and “net 2 ATP” for anaerobic processes.

Conclusion: Aerobic respiration completely oxidises glucose with O2 and high ATP yield, anaerobic respiration/fermentation does not; glycolysis is cytoplasmic and universal, fermentation and the citric acid cycle are alternative fates of pyruvate under anaerobic and aerobic conditions respectively.

Q8

What are the assumptions made during the calculation of net gain of ATP?

Answer

Concept. It is possible to calculate the net gain of ATP for every glucose molecule oxidised, but NCERT stresses that this “can remain only a theoretical exercise”, because the calculation holds only on certain assumptions.

  1. Sequential, orderly pathway. There is a sequential, orderly pathway functioning, with one substrate forming the next, and glycolysis, TCA cycle and ETS following one after another.
  2. Glycolytic NADH is transferred and oxidised. The NADH synthesised in glycolysis is transferred into the mitochondria and undergoes oxidative phosphorylation.
  3. No diversion of intermediates. None of the intermediates in the pathway is utilised to synthesise any other compound.
  4. Only glucose is respired. No other alternative substrates enter the pathway at any of the intermediary stages.
StageReduced coenzyme / ATPATP
GlycolysisNet 2 ATP; 2 NADH × 32 + 6 = 8
Link reaction2 NADH × 36
Krebs’ cycle6 NADH × 3 = 18; 2 FADH2 × 2 = 4; 2 ATP (GTP)24
Total38 ATP

Why the assumptions fail in a living cell. All pathways work simultaneously and do not take place one after another; substrates enter the pathways and are withdrawn as and when necessary; ATP is utilised as and when needed; enzymatic rates are controlled by multiple means. Yet the exercise is useful to appreciate the beauty and efficiency of the living system in extracting and storing energy — hence a net gain of 38 ATP per glucose in aerobic respiration.

Exam tip: Give all four assumptions as separate bullet points and end with the figure 38 ATP — NCERT uses 3 ATP per NADH and 2 per FADH2.
Exam tip: A common follow-up: “Why is this value theoretical only” — answer that real cells use intermediates for biosynthesis and use other substrates.

Conclusion: The net 38 ATP per glucose rests on four assumptions — sequential pathways, transfer of glycolytic NADH to mitochondria, no diversion of intermediates and glucose as sole substrate — none of which strictly holds in a living cell.

Q9

Discuss “The respiratory pathway is an amphibolic pathway.”

Answer

Concept. Breaking down processes within a living organism are catabolism; synthesis is anabolism. Since respiration involves the breakdown of substrates, it has traditionally been considered a catabolic process and the respiratory pathway a catabolic pathway. NCERT asks whether this understanding is correct — and shows that it is not the whole truth.

Interrelationship among metabolic pathwaysInterrelationship among metabolic pathways: respiration of different organic moleculesPolysaccharides (starch, sucrose)GlucoseGlucose-6-phosphate → fructose-1,6-bisphosphateTriose phosphate (PGAL)GLYCOLYSISPyruvic acid(mitochondria)Acetyl CoAKREBS’ CYCLE(citric acid cycle)ETS → CO₂ + H₂O + energy (ATP)FatsGlycerolFatty acidsGlycerol enters as PGALFatty acids are degraded toacetyl CoA before enteringProteinsproteasesAmino acidsAmino acids (after deamination) enter atpyruvate, acetyl CoA or a Krebs’ cycle stepDouble-headed arrows: the same intermediates are withdrawn for synthesis (anabolism) — so the respiratory pathway is amphibolic.© iBioKaare
Fig. — Interrelationship among metabolic pathways showing respiration-mediated breakdown of different organic molecules to CO2 and H2O (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.6, PDF page 11 (book page 163) ↗
  • Catabolic entry of substrates. Glucose is the favoured substrate and all carbohydrates are first converted into glucose. Fats are broken into glycerol and fatty acids; fatty acids are degraded to acetyl CoA and glycerol enters after conversion to PGAL. Proteins are degraded by proteases to amino acids, which after deamination enter at pyruvate, acetyl CoA or a Krebs’ cycle step.
  • Anabolic withdrawal of the same intermediates. It is these very compounds that would be withdrawn from the respiratory pathway for the synthesis of the said substrates. When the organism needs to synthesise fatty acids, acetyl CoA is withdrawn from the pathway; similarly, during breakdown and synthesis of proteins, respiratory intermediates form the link.
  • Conclusion of the argument. The respiratory pathway therefore comes into the picture both during breakdown and during synthesis, i.e., it serves both catabolism and anabolism, and is better described as an amphibolic pathway (amphi = both) rather than purely catabolic.
SubstrateCatabolism: enters respiration asAnabolism: withdrawn from pathway for
Fatty acidsAcetyl CoASynthesis of fatty acids (acetyl CoA withdrawn)
GlycerolPGAL (glycolytic intermediate)Synthesis of fats (glycerol part)
Amino acids / proteinsPyruvate, acetyl CoA or Krebs’ cycle intermediates after deaminationSynthesis of amino acids and proteins from respiratory intermediates
CarbohydratesGlucose → glycolysisIntermediates for carbohydrate synthesis

Extra depth. The carbon skeletons produced during respiration are used as precursors for biosynthesis of other molecules in the cell (stated in the chapter introduction). This is why one pathway can connect carbohydrate, fat and protein metabolism, as shown in the interrelationship diagram.

Exam tip: Define catabolism and anabolism first, then give one explicit example (acetyl CoA used for fatty acid breakdown and synthesis).
Exam tip: Use the word “amphibolic” with its meaning (both) — and draw or cite Fig. 12.6 for full marks.

Conclusion: Because respiratory intermediates are both used up for energy and withdrawn for biosynthesis of fats, proteins and carbohydrates, the respiratory pathway is amphibolic, not merely catabolic.

Q10

Define RQ. What is its value for fats?

Answer

Definition. The ratio of the volume of CO2 evolved to the volume of O2 consumed in respiration is called the respiratory quotient (RQ) or respiratory ratio.

RQ = volume of CO2 evolved ÷ volume of O2 consumed

Value for fats. When fats are used in respiration, the RQ is less than 1. For tripalmitin, taken as the example substrate:

2(C51H98O6) + 145 O2 → 102 CO2 + 98 H2O + energy

RQ = 102 CO2 ÷ 145 O2 = 0.7

Fats contain much less oxygen in their molecules than carbohydrates, so a larger volume of external O2 is needed for their complete oxidation than the CO2 evolved — hence RQ is below 1.

Respiratory substrateEquation / basisRQ
Carbohydrate (glucose)C6H12O6 + 6O2 → 6CO2 + 6H2O + energy; 6CO2/6O21.0
Fat (tripalmitin)102CO2/145O20.7
ProteinGiven in NCERT as about0.9

Extra depth. RQ depends on the type of respiratory substrate. In living organisms the substrates are often more than one — pure proteins or fats are never used as respiratory substrates — so the observed RQ of a tissue is usually between these values.

Exam tip: Write the full tripalmitin equation (2 C51H98O6 + 145 O2 → 102 CO2 + 98 H2O) and the division 102/145 = 0.7 — examiners award marks for the working.
Exam tip: Memory aid: carbohydrate 1.0 > protein 0.9 > fat 0.7.

Conclusion: RQ is the ratio of CO2 evolved to O2 consumed; for fats it is about 0.7 (less than 1).

Q11

What is oxidative phosphorylation?

Answer

Definition. Oxidative phosphorylation is the synthesis of ATP from ADP and inorganic phosphate by ATP synthase, using the energy released as electrons are passed from NADH + H+ and FADH2 through the electron transport system to molecular oxygen. It takes place on the inner mitochondrial membrane.

Diagrammatic presentation of ATP synthesis in mitochondriaATP synthesis in mitochondria (ATP synthase, complex V)INTERMEMBRANE SPACEMATRIXF₀ (channel)F₁(head piece)H⁺H⁺H⁺ADP + iPATPFor each ATP produced, 4 H⁺ passthrough F₀ from the intermembranespace to the matrixF₀ = integral membraneprotein complex (proton channel)F₁ = peripheral head piece(site of ATP synthesis)© iBioKaare
Fig. — Diagrammatic presentation of ATP synthesis in mitochondria (ATP synthase, F1 and F0) (original iBioKaare schematic). Compare with NCERT textbook — Fig. 12.5, PDF page 9 (book page 161) ↗
  • Why “oxidative”. Unlike photophosphorylation where it is light energy that is utilised for the production of the proton gradient, in respiration it is the energy of oxidation–reduction that is utilised for the same process; hence the name oxidative phosphorylation.
  • Mechanism — chemiosmosis. The energy released during electron transport is utilised in synthesising ATP with the help of ATP synthase (complex V), as explained by the chemiosmotic hypothesis.
  • Structure of ATP synthase. It consists of two major components, F1 and F0. The F1 headpiece is a peripheral membrane protein complex containing the site for synthesis of ATP from ADP and inorganic phosphate. F0 is an integral membrane protein complex forming the channel through which protons cross the inner membrane.
  • Proton flow. The passage of protons through the channel is coupled to the catalytic site of F1. For each ATP produced, 4H+ pass through F0 from the intermembrane space to the matrix down the electrochemical proton gradient.
  • Role of oxygen. O2 is the ultimate electron acceptor and is reduced to water; it drives the whole process by removing hydrogen from the system.

Yield. One NADH gives 3 ATP and one FADH2 gives 2 ATP.

Extra depth. The proton gradient is established across the inner mitochondrial membrane (high H+ in the intermembrane space, low in the matrix); ATP synthase turns this electrochemical gradient into chemical energy. Together, glycolysis, the Krebs’ cycle and oxidative phosphorylation give the theoretical net gain of 38 ATP per glucose (see Q8).

Exam tip: Contrast with photophosphorylation in one line — light energy there, redox energy here.
Exam tip: Label F1 (headpiece, ATP made) and F0 (membrane channel) and quote “4H+ per ATP”.

Conclusion: Oxidative phosphorylation is the ATP synthesis driven by the redox energy of the ETS, with O2 as final acceptor, occurring through ATP synthase in the inner mitochondrial membrane.

Q12

What is the significance of step-wise release of energy in respiration?

Answer

Concept. The complete combustion of glucose produces CO2 and H2O as end products, but most of the energy is given out as heat. If the energy is to be useful, the cell must be able to use it to synthesise other molecules it requires.

  • Avoids loss as heat. The strategy of the plant cell is to catabolise glucose in such a way that not all the liberated energy goes out as heat; oxidising glucose not in one step but in several small steps lets some steps be just large enough for the energy released to be coupled to ATP synthesis.
  • Energy is trapped as ATP. Because the energy is released in a series of slow step-wise reactions controlled by enzymes, it is trapped as chemical energy in ATP, which is broken down whenever and wherever energy is needed. Energy released in respiration cannot be used directly; it is used to synthesise ATP, the energy currency of the cell.
  • Control by enzymes. Each step is controlled by a specific enzyme, so the rate of energy release matches cellular needs and the cell is protected from sudden temperature rise that would damage it.
  • Carbon skeletons for biosynthesis. The intermediate compounds produced act as carbon skeletons and precursors for biosynthesis of other molecules (amphibolic role).
Step-wise (in cells)Single step (combustion)
Small amounts of energy released at each enzyme stepAll energy released at once
Part trapped as ATPAlmost all lost as heat
Enzyme-controlled, at body temperatureUncontrolled, high temperature
Intermediates available for biosynthesisNo useful intermediates

Extra depth. Both the intermediates and the ATP obtained step by step serve the cell: ATP supplies energy wherever it is needed, and respiratory intermediates (e.g., acetyl CoA) are drawn off for fatty acid and protein synthesis. In contrast, a fire converts the same glucose into heat and light only. This is also why fermentation, with its minimal 2 ATP, wastes most of the chemical energy still locked in ethanol or lactic acid.

Exam tip: Use the phrases “not lost as heat”, “trapped in ATP” and “enzyme-controlled” — these are the NCERT keywords.
Exam tip: Link to Q1(a): this is exactly why respiration differs from combustion.

Conclusion: Step-wise release lets the cell capture energy as ATP and intermediates for biosynthesis instead of wasting it as heat.

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